AB and AC are equal legs in triangle ABC. Point D lies on AB such that CD = CB. If angle ADC = 114 degrees, what is angle ACD in degrees?

$\angle ACD = 22^\circ$.

Angle ACD = 18 degrees

ADC =114 so we know BDC is then equal to 66 (180-114)

DBC is also equal to BDC because its an isosceles traingle, DBC and BDC = 66

180-(66+66)=48

because AB and AC are equal sides, ABC and ACB are both equal to 66

66-48=12 :)